Jan 07 2011 - Diluting Solutions to Prepare Workable Solutions

We learned how to calculate diluting solutions.



Key idea - the moles of solute is constant (i.e. the only difference is that there is more water in the less concentrated solution)
moles before = moles after
Equation : M1L1=M2L2 (1 denotes "before")


For example, 20.0 mL of 0.200 M NaOH solution is diluted to a final volume of 100.0 mL, calculate the new concentration.

M1 = 0.200 M NaOH

L1 = 20.0mL

M2 = ?

L2 = 100.0 mL
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaM1L1=M2L2

aaaaaaaaaaaaa 0.200 M NaOH x 20.0 mL = M2 x 100.0 mL
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa0.200 x 20.0
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaM2 =__________________
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa100.0
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaM2 = 0.200 M

The video for practice problems on dilution calculations